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Physiology · Muscle physiology: smooth muscle
Sample itemIn smooth muscle, how does a rise in intracellular calcium produce contraction?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
C. Calcium binds calmodulin, which activates myosin light-chain kinase to phosphorylate myosin
Smooth muscle has no troponin. Calcium binds calmodulin, and the complex activates myosin light-chain kinase, which phosphorylates the regulatory light chain of myosin and permits cross-bridge cycling. Myosin light-chain phosphatase reverses this and relaxes the muscle.
Option by option
A. Calcium inhibits myosin phosphatase only, with no kinase activation
Inhibition of the phosphatase may sustain contraction but the primary step is kinase activation.
B. Calcium binds troponin C and moves tropomyosin off the actin binding sites
This is the mechanism of skeletal and cardiac muscle, which have troponin.
C. Calcium binds calmodulin, which activates myosin light-chain kinase to phosphorylate myosin (correct)
Correct. The calcium-calmodulin complex activates myosin light-chain kinase.
D. Calcium directly binds actin to expose the myosin head
Calcium acts through regulatory proteins, not by binding actin directly.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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