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Biochemistry · Carbohydrate chemistry: reducing sugars
Sample itemA fresh sucrose solution gives a negative Benedict test, but the test becomes positive after the solution is boiled with dilute acid. What is the best explanation?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
D. Its glucose and fructose are joined through both anomeric carbons, so no free reducing group exists until hydrolysis
Sucrose is glucose alpha 1-beta 2 fructose, so the anomeric carbons of both units are locked in the glycosidic bond and neither can open to expose an aldehyde or ketol group. Acid hydrolysis releases free glucose and fructose, which are reducing sugars. Lactose and maltose keep a free anomeric carbon and are reducing.
Option by option
A. Sucrose is a monosaccharide with no anomeric carbon
Sucrose is a disaccharide, and the issue is that its anomeric carbons are bonded together.
B. Fructose is unable to reduce cupric ions in alkaline medium
Fructose reduces in alkali because it tautomerises through an enediol to an aldose.
C. Sucrose has a beta 1-4 linkage that acid cannot hydrolyse
Sucrose has an alpha 1-beta 2 linkage, and dilute acid readily hydrolyses it; beta 1-4 is the lactose linkage.
D. Its glucose and fructose are joined through both anomeric carbons, so no free reducing group exists until hydrolysis (correct)
Correct. Both anomeric carbons are engaged, so sucrose is a non-reducing disaccharide.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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