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Biochemistry · Enzyme kinetics: Michaelis-Menten calculation
Sample itemAn enzyme has a Vmax of 100 micromol per minute and a Km of 2 mM. What is the initial velocity at a substrate concentration of 0.5 mM?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
D. 20 micromol per minute
The Michaelis-Menten equation is v = Vmax [S] / (Km + [S]). Substituting gives v = 100 x 0.5 / (2 + 0.5) = 50 / 2.5 = 20 micromol per minute. Velocity reaches half of Vmax only when [S] equals Km.
Option by option
A. 25 micromol per minute
25 would be obtained by wrongly using [S] / Km as the fraction of Vmax.
B. 50 micromol per minute
50 would be the velocity only if [S] were equal to Km (2 mM).
C. 33 micromol per minute
33 would be the velocity if [S] were 1 mM (100 x 1 / 3).
D. 20 micromol per minute (correct)
Correct. 100 x 0.5 / 2.5 = 20.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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