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Biochemistry · Minerals: corrected calcium
Sample itemA 30-year-old woman with nephrotic syndrome has no tetany. Serum total calcium is 7.2 mg/dL and albumin is 2.0 g/dL. Using the correction of 0.8 mg/dL of calcium for every 1 g/dL that albumin is below 4.0, what is the interpretation?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
C. Corrected calcium is about 8.8 mg/dL, which is normal, so no calcium replacement is needed
Corrected calcium equals measured calcium plus 0.8 x (4.0 minus albumin). Here it is 7.2 + 0.8 x 2.0 = 7.2 + 1.6 = 8.8 mg/dL. Low total calcium from hypoalbuminaemia reflects reduced protein-bound calcium, while the ionised fraction is normal. Ionised calcium can be measured if there is doubt.
Option by option
A. Corrected calcium is about 5.6 mg/dL, which needs intravenous calcium gluconate
5.6 results from subtracting the correction (7.2 minus 1.6) instead of adding it.
B. Corrected calcium is 7.2 mg/dL, which needs oral calcium
Ignoring albumin treats the low protein-bound fraction as true hypocalcaemia.
C. Corrected calcium is about 8.8 mg/dL, which is normal, so no calcium replacement is needed (correct)
7.2 plus 1.6 gives 8.8, which is within the normal range, so the ionised calcium is normal.
D. Corrected calcium is about 10.4 mg/dL, which indicates hypercalcaemia
10.4 results from doubling the correction to 3.2, which is arithmetically wrong.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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