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Biochemistry · Glycolysis: arsenate and ATP yield
Sample itemArsenate can substitute for inorganic phosphate at glyceraldehyde-3-phosphate dehydrogenase. The resulting 1-arseno-3-phosphoglycerate hydrolyses spontaneously, so phosphoglycerate kinase is bypassed. What is the net ATP yield from anaerobic glycolysis of one glucose molecule in this situation?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
C. Zero
Normally glycolysis consumes 2 ATP in the preparatory phase and makes 2 ATP at phosphoglycerate kinase and 2 at pyruvate kinase, a net 2. With arsenate the 2 ATP made at phosphoglycerate kinase are lost, leaving 2 (pyruvate kinase) minus 2 (investment), which equals zero. The pathway proceeds but yields no net energy.
Option by option
A. Two
Two is the normal net yield, which requires the phosphoglycerate kinase step that arsenate bypasses.
B. Minus two
Minus two would require pyruvate kinase to fail as well, which arsenate does not cause.
C. Zero (correct)
Two ATP are used and only the two from pyruvate kinase are made, so net ATP is 0.
D. Four
Four is the gross yield in normal glycolysis and ignores the 2 ATP invested and the lost kinase step.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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