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Biochemistry · Clinical biochemistry: corrected calcium
Sample itemA malnourished patient with nephrotic syndrome has a total serum calcium of 7.2 mg/dL and albumin of 2.0 g/dL. Using the standard correction, what is the albumin-corrected calcium and what does it mean?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
A. 8.8 mg/dL, which is within the normal range
Corrected calcium = measured calcium + 0.8 x (4.0 - albumin) = 7.2 + 0.8 x 2.0 = 8.8 mg/dL. About 40% of calcium is protein-bound, so low albumin lowers total calcium without changing the physiologically active ionised fraction. Ionised calcium measurement is the best test when in doubt.
Option by option
A. 8.8 mg/dL, which is within the normal range (correct)
Correct. After correction the value of 8.8 mg/dL is normal, a pseudohypocalcaemia.
B. 7.2 mg/dL, which is unchanged by albumin
Albumin binding does alter total calcium, so no correction would be wrong here.
C. 9.6 mg/dL, which is hypercalcaemia
9.6 mg/dL is not the result of the formula, and the patient is not hypercalcaemic.
D. 6.4 mg/dL, which is severe hypocalcaemia
Subtracting the correction instead of adding it is the error behind 6.4 mg/dL.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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