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Physiology · Respiratory system: alveolar-arterial gradient
Sample itemA 25-year-old man is found drowsy with slow, shallow breathing after an opioid overdose. On room air (FiO2 0.21, barometric pressure 760 mmHg, water vapour 47 mmHg, R = 0.8) his PaO2 is 55 mmHg and PaCO2 is 70 mmHg. What is his A-a gradient and what does it show?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
A. About 7 mmHg, which is normal, so hypoventilation alone explains the hypoxaemia
PAO2 = FiO2 x (PB - PH2O) - PaCO2/R = 0.21 x 713 - 70/0.8 = 149.7 - 87.5 = about 62 mmHg. The A-a gradient is 62 - 55 = about 7 mmHg, which is normal for a young adult. A normal gradient with raised PaCO2 means the lungs transfer oxygen normally and the hypoxaemia is from reduced alveolar ventilation.
Option by option
A. About 7 mmHg, which is normal, so hypoventilation alone explains the hypoxaemia (correct)
The gradient is about 7 mmHg, so the lungs are normal and the fault is central hypoventilation.
B. About 45 mmHg, which is raised, so a diffusion defect explains the hypoxaemia
45 mmHg arises only if the raised PaCO2 is ignored and 40 is assumed, which overstates the gradient.
C. About 95 mmHg, which is raised, so a right-to-left shunt explains the hypoxaemia
95 mmHg arises only if the CO2 term is left out completely.
D. About 62 mmHg, which is raised, so ventilation-perfusion mismatch explains the hypoxaemia
62 mmHg is the calculated alveolar PO2, not the gradient.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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