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Physiology · Renal: creatinine clearance
Sample itemA patient has plasma creatinine 1 mg/dL, urine creatinine 60 mg/dL and urine flow 2 mL/min. What is the creatinine clearance?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
C. 120 mL/min
Clearance = urine concentration multiplied by urine flow divided by plasma concentration. Here 60 x 2 / 1 = 120 mL/min. Creatinine is freely filtered and slightly secreted, so its clearance approximates, and slightly overestimates, the glomerular filtration rate.
Option by option
A. 240 mL/min
This doubles the correct result and has no arithmetic basis.
B. 60 mL/min
This ignores the urine flow term; 60/1 gives 60.
C. 120 mL/min (correct)
Correct. 60 x 2 / 1 = 120 mL/min.
D. 30 mL/min
This results from dividing by 2 instead of multiplying.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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