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Physiology · Muscle physiology: length-tension relation
Sample itemIn an isolated skeletal muscle experiment, the muscle is progressively stretched before stimulation. Active force is greatest at a sarcomere length of about 2.2 micrometres and falls to almost zero beyond about 3.6 micrometres. What explains the near-zero force at 3.6 micrometres?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
D. Thick and thin filaments no longer overlap, so no cross bridges can form
Active tension depends on the number of cross bridges between overlapping thick and thin filaments. At optimal length, overlap is maximal without interference. At very long lengths the filaments are pulled apart, so cross bridge formation is minimal, whereas at short lengths thin filaments overlap one another and force falls too.
Option by option
A. The thin filaments collide in the centre of the sarcomere
Collision of thin filaments reduces force at short lengths, not at extreme stretch.
B. All myosin heads are detached because ATP is exhausted
ATP is not exhausted in the experiment; the force loss is geometric.
C. Calcium release from the sarcoplasmic reticulum is abolished by stretch
Calcium release is unaffected by moderate muscle stretch, which acts mechanically on filament overlap.
D. Thick and thin filaments no longer overlap, so no cross bridges can form (correct)
At 3.6 micrometres there is virtually no overlap, so force is almost zero.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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