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Biochemistry · Molecular biology and genetics: JAK2 V617F mutation
Sample itemA 55-year-old man has a raised haemoglobin, itching after a hot bath and splenomegaly. Bone marrow shows panmyelosis. A somatic mutation in which gene is found in most such patients?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
A. JAK2 (V617F)
The JAK2 V617F mutation causes constitutive tyrosine kinase activity, making erythropoietin-receptor signalling independent of ligand. It is found in almost all cases of polycythaemia vera and in about half of essential thrombocythaemia and primary myelofibrosis. Ruxolitinib is a JAK inhibitor used in treatment.
Option by option
A. JAK2 (V617F) (correct)
Correct. JAK2 V617F drives ligand-independent proliferation in polycythaemia vera.
B. RB1
RB1 is a tumour suppressor mutated in retinoblastoma.
C. BCR-ABL1
BCR-ABL1 defines chronic myeloid leukaemia, which usually gives leucocytosis rather than isolated erythrocytosis.
D. KIT
KIT mutations are found in mastocytosis and gastrointestinal stromal tumours.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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