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Biochemistry · Clinical biochemistry: chloride shift
Sample itemThe chloride content of red cells in venous blood is higher than in arterial blood. Which process explains this?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
D. Bicarbonate leaves the red cell in exchange for chloride through the band 3 anion exchanger
In the tissues, CO2 enters the red cell and is hydrated by carbonic anhydrase to bicarbonate. Bicarbonate then leaves the cell via the band 3 anion exchanger in exchange for chloride, which keeps the cell electrically neutral. This is the chloride shift or Hamburger phenomenon, reversed in the lungs.
Option by option
A. Chloride enters red cells with potassium through the Na-K-2Cl cotransporter
Red cells do not rely on the Na-K-2Cl cotransporter for this shift.
B. Chloride binds to deoxyhaemoglobin at the haem group
Deoxyhaemoglobin binds protons and CO2, but chloride does not bind at the haem group.
C. Chloride is pumped in by the sodium-potassium ATPase
The sodium-potassium ATPase pumps sodium and potassium, not chloride.
D. Bicarbonate leaves the red cell in exchange for chloride through the band 3 anion exchanger (correct)
Correct. HCO3- out and Cl- in through band 3 keeps the cell electroneutral as CO2 is carried.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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