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Biochemistry · Nucleotide metabolism: secondary hyperuricaemia in psoriasis
Sample itemA man with extensive psoriasis, normal renal function and no medication has a serum urate of 9 mg/dL. Which mechanism most likely explains this?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
B. Rapid cell turnover increasing nucleic acid breakdown to uric acid
Conditions with accelerated cell turnover, including psoriasis, leukaemia and haemolysis, increase nucleic acid catabolism, so more purine is converted to uric acid. Lack of uricase is universal in humans, so it cannot explain a raised level in one person.
Option by option
A. Deficient xanthine oxidase blocking the last step of purine degradation
Xanthine oxidase deficiency would lower urate rather than raise it.
B. Rapid cell turnover increasing nucleic acid breakdown to uric acid (correct)
Correct. High epidermal cell turnover releases more purines for degradation.
C. Absence of uricase in all humans, causing the raised urate
All humans lack uricase, so this is not why this patient differs from others.
D. HGPRT deficiency raising PRPP and de novo purine synthesis
HGPRT deficiency is a rare X-linked disorder with neurological features, not an explanation in a skin disease.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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