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Pharmacology · General pharmacology: zero-order kinetics
Sample itemA man drinks heavily and his blood alcohol falls by roughly the same amount every hour, whether the level is high or low. Which kinetic pattern does this describe?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
A. Zero-order elimination, a constant amount removed per unit time because enzymes are saturated
With zero-order (saturation) kinetics the elimination enzyme works at maximum capacity, so a fixed amount of drug is removed per hour regardless of concentration. Alcohol, phenytoin at higher doses and high-dose aspirin behave this way, and a small dose increase can produce a disproportionate rise in level.
Option by option
A. Zero-order elimination, a constant amount removed per unit time because enzymes are saturated (correct)
Correct. A constant amount per hour at any concentration is the definition of zero-order kinetics.
B. First-order elimination, a constant fraction removed per unit time
Under first-order kinetics the amount eliminated falls as the concentration falls, since a fixed fraction is cleared.
C. Two-compartment redistribution with a rapid alpha phase
Redistribution describes a fast initial fall between compartments, not a steady linear decline.
D. Flip-flop kinetics caused by slow absorption
Flip-flop kinetics refers to absorption being slower than elimination, which does not explain a constant hourly fall.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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