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Orthopaedics · Spinal cord injury
Sample itemA man is stabbed on the right side of his back at the T10 level. On examination, he has right leg weakness with loss of vibration and position sense on the right, and loss of pain and temperature sensation on the left from about the T12 level downwards. What explains the sensory findings on the left?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
C. Spinothalamic fibres cross within one or two segments of entering the cord, so a right hemisection affects the contralateral pain pathway below the lesion
Brown-Séquard syndrome is a hemisection of the cord. The ipsilateral side has upper motor neurone weakness and loss of dorsal column function (vibration, proprioception), and the contralateral side loses pain and temperature because spinothalamic fibres decussate in the anterior white commissure close to their level of entry.
Option by option
A. Corticospinal tract fibres carry pain sensation from the opposite side
The corticospinal tract is a motor pathway.
B. The posterior columns cross in the cord and carry pain
The dorsal columns ascend ipsilaterally and decussate in the medulla, and carry fine touch and proprioception.
C. Spinothalamic fibres cross within one or two segments of entering the cord, so a right hemisection affects the contralateral pain pathway below the lesion (correct)
Correct. Fibres carrying pain from the left side cross to the right cord before ascending, and are cut by a right hemisection.
D. Spinothalamic fibres ascend uncrossed, so the left side is affected
Spinothalamic fibres cross rather than ascending uncrossed.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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