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Anatomy · Genetics: Hardy-Weinberg calculation
Sample itemAn autosomal recessive disorder occurs in 1 in 10,000 births in a population in Hardy-Weinberg equilibrium. What is the approximate carrier frequency?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
D. About 1 in 50
If q squared is 1/10,000, then q is 1/100 or 0.01, and p is 0.99. Carrier frequency is 2pq, which is 2 x 0.99 x 0.01 = 0.0198, or about 1 in 50. Carriers are therefore far more common than affected people.
Option by option
A. About 1 in 10
A carrier frequency of 1 in 10 would give an incidence of about 1 in 400, far higher than stated.
B. About 1 in 5,000
This merely doubles the disease incidence and has no basis in the Hardy-Weinberg equation.
C. About 1 in 100
This is the allele frequency q (1 in 100), not the carrier frequency, which is about double.
D. About 1 in 50 (correct)
Correct. 2pq = 2 x 0.99 x 0.01 = 0.0198, about 1 in 50.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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