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Pharmacology · Pharmacokinetics: drug metabolism in liver disease
Sample itemA 55-year-old man with decompensated alcoholic cirrhosis needs a benzodiazepine for alcohol withdrawal. Which agent is preferred, and why?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
C. Lorazepam, because glucuronidation is relatively preserved and it has no active metabolites
Lorazepam and oxazepam are cleared by phase II glucuronidation, which is relatively spared in cirrhosis, and they have no active metabolites. Diazepam and chlordiazepoxide undergo phase I oxidation to long-lived active metabolites that accumulate and risk precipitating hepatic encephalopathy.
Option by option
A. Chlordiazepoxide, because its metabolites are inactive
Chlordiazepoxide has long-acting active metabolites such as desmethyldiazepam.
B. Flurazepam, because it has the shortest duration
Flurazepam has a very long-acting active metabolite and is a hypnotic, not a short-acting agent.
C. Lorazepam, because glucuronidation is relatively preserved and it has no active metabolites (correct)
Correct. Conjugation with no active metabolites gives predictable effect in hepatic impairment.
D. Diazepam, because it is cleared by oxidation even in liver failure
Diazepam is cleared by oxidation, which is impaired in cirrhosis, and its metabolites accumulate.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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