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Anatomy · Embryology: sex determination
Sample itemA phenotypic female has primary amenorrhoea, a normal uterus and streak gonads, and a 46,XY karyotype. Which gene is most likely mutated?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
D. SRY
Loss of the testis-determining SRY gene means the gonads do not form testes, so there is no anti-Mullerian hormone or testosterone. The uterus and tubes persist and the external genitalia are female, as in Swyer syndrome.
Option by option
A. SRD5A2
SRD5A2 deficiency leaves testes and causes ambiguous genitalia that virilise at puberty.
B. Anti-Mullerian hormone gene
Anti-Mullerian hormone gene loss gives a male phenotype with persistent Mullerian structures.
C. Androgen receptor gene
Androgen receptor defects leave functioning testes that secrete anti-Mullerian hormone, so no uterus is present.
D. SRY (correct)
Correct. Loss of SRY leaves streak gonads and a female phenotype in a 46,XY individual.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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