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Radiology · Contrast agents: effect of tube voltage on iodine contrast
Sample itemA radiologist lowers the tube voltage for a CT angiogram in a slim patient and finds that vessels enhance more brightly at the same iodine dose. What physical principle explains this?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
A. Lower photon energy lies closer to the K-edge of iodine, so photoelectric absorption by iodine rises
Iodine has a K-edge near 33 keV, and photoelectric absorption jumps just above it. Lower kV shifts the mean photon energy towards the K-edge, so iodinated vessels appear brighter or less contrast is needed. The trade-off is more noise in large patients.
Option by option
A. Lower photon energy lies closer to the K-edge of iodine, so photoelectric absorption by iodine rises (correct)
Correct. Photoelectric absorption by iodine increases near its K-edge.
B. Lower kV reduces beam hardening in the vessel
Beam hardening is not the reason for brighter vessels.
C. Iodine emits fluorescence that adds signal
Fluorescence does not contribute to CT signal.
D. Iodine attenuates by Compton scatter, which increases at low kV
Compton scatter is largely independent of atomic number and falls with energy.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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