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Pathology · Cell injury: cyanide poisoning
Sample itemA worker is found collapsed after drinking an electroplating solution. He has cherry-red skin and severe lactic acidosis, venous blood is bright red, and PaO2 is normal. Which step of cellular respiration is blocked, and why is lactate high?
Original practice item, not a recalled exam question. Nothing here is recorded.
The answer and the reasoning
B. Cytochrome c oxidase is inhibited, halting oxidative phosphorylation and forcing anaerobic glycolysis
Cyanide binds the ferric iron of cytochrome c oxidase (complex IV), so tissues cannot use oxygen even though delivery is normal. Venous blood stays oxygen rich, hence the bright red colour and narrow arteriovenous oxygen difference. Cells shift to anaerobic glycolysis, producing lactic acidosis.
Option by option
A. Carboxyhaemoglobin formation limits oxygen carriage while tissue oxygen utilisation stays normal
Carbon monoxide poisoning also gives cherry-red skin but reduces oxygen content and carriage, and the setting here is an electroplating cyanide solution.
B. Cytochrome c oxidase is inhibited, halting oxidative phosphorylation and forcing anaerobic glycolysis (correct)
Correct. Blocked complex IV explains normal PaO2, bright venous blood and lactic acidosis.
C. Methaemoglobin formation prevents oxygen binding, so tissues extract oxygen normally from plasma
Methaemoglobinaemia produces chocolate-brown blood and cyanosis, and does not match bright red venous blood.
D. Mitochondrial proton gradient uncoupling dissipates energy as heat, causing hyperthermia
Uncoupling, as with dinitrophenol, causes hyperthermia with increased oxygen consumption, not a narrowed arteriovenous oxygen difference.
Source note: Original NextPrep sample item — pending expert review. This item is original practice material awaiting independent expert review, so confirm important facts in a standard textbook.
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